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Kazhiim
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Oh my god. I am dying here. Fuck statics.

I need to find the tension of each line segment (except the two holding the weights) such that the system is in equilibrium, as well as the missing angle. I know that the x- and y-axis components need to equal zero, but every equation I come up with has too many variables.

I'm completely fucking stumped. Not asking for the answer, since that's verboten, but even a little hint as to the equation I'm setting up would be nice. Thanks.

I need to find the tension of each line segment (except the two holding the weights) such that the system is in equilibrium, as well as the missing angle. I know that the x- and y-axis components need to equal zero, but every equation I come up with has too many variables.

I'm completely fucking stumped. Not asking for the answer, since that's verboten, but even a little hint as to the equation I'm setting up would be nice. Thanks.

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## Posts

The one on the left has 60 lb down, F1 in the direction of rope, and F2 right. You know that F1(y direction)=F1sin(50)=60 lb, so solve for F1. F1cos(50) = tension left, which also has to equal tension right. You now know the tension to the left of the weight on the right, as well as the weight. Take the arctan of this and you have your answer.

Make sense?

shadydentistonGT: Tanky the Tank

Black: 1377 6749 7425

First find the tension in the 50 degree string by balancing the vertical forces in the left knot. Then find the tension in the middle string by balancing the horizontal forces in the left knot. Then set up two equations with two unknowns to find the tension and angle of the rightmost string.

HirocononI am dumber than shit

Kazhiimon