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Fizban140
Registered User, __BANNED USERS

Just don't understand the mystery rule here, I got the asnwer in the back of the book I just don't know why they did it like this.

1+1/x

1/x

Why doesn't the 1/x just cancel out the top one to make it one? I guess the book wants me to do x/1 (1/x) but I am not sure why you don't cancel it out. Obviously both can't work since the former gives me 1 and the latter 1+x

1+1/x

1/x

Why doesn't the 1/x just cancel out the top one to make it one? I guess the book wants me to do x/1 (1/x) but I am not sure why you don't cancel it out. Obviously both can't work since the former gives me 1 and the latter 1+x

## Posts

I hope you understand, and like the way that I am

Dear Satan...

termIf you're talking about canceling something the entire term must possess the element you want to cancel. So in this case you would only be able to cancel out the 1/x if the top term was 1/x(1+1/x) or 1/x + (1/x)*(1/x)

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Basically -> [1 + (1/x) ] / (1/x) = [1 / (1/x) ] + [(1/x) / (1/x)]

Does that make sense?

from here you can see that [(1/x) / (1/x)] = 1 and you can figure out that [1 / (1/x) ] = x

and thus this = x+1

does this help at all?

A + B

C

this expression is the same as

A + B

--- ----

C C

To us an example that is more of the form of your question; it would be like this:

A + C

C

=

A + C

--- ----

C C

A + B

B

You cannot cancel out because both of the terms in the numerator must have the term you're trying to cancel out; these are just the rules of math.

Think of it as doing the opposite of the distributive property [ie A(B+C) = AB + AC], that is, in order to cancel out an element from the term, every single element of that term must have the element which you are trying to factor out or cancel out. For instance if you had

AB + CB

B

You can cancel out the B and end up with A + B

You can also think of this as factoring B out of the expression and turning it into B(A+C)

However in the example you have and in this example

A + B

B

You cannot do so because the entire term does not have B in it. If you were to try to factor out B from the term A + B you would be unable to do so, and that is your problem.

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The key thing to know here is that if you multiply the numerator and the denominator by the same thing, the fraction remains unchanged (because x/x = 1 and multiplying by 1 changes nothing)

(1 + 1/x) / (1/x)

= (x * (1 + 1/x)) / (x * (1/x))

= (x + 1) / (1)

= x + 1

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