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Coefficient

RhinoRhino TheRhinLOLRegistered User regular
edited September 2009 in Help / Advice Forum
Can someone explain this to me in layman terms? I googled it, but don't think I understand it.

Also how are the variable, numerical, true, and real coefficients defined?

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Posts

  • ecco the dolphinecco the dolphin Registered User regular
    edited September 2009
    In what context?

    ecco the dolphin on
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  • Casually HardcoreCasually Hardcore Once an Asshole. Trying to be better. Registered User regular
    edited September 2009
    It's the number in front of your variable.

    Casually Hardcore on
  • SkyEyeSkyEye Registered User regular
    edited September 2009
    Basically, you simply take the coefficient and multiply it by the variable term its in front of. ex. 15x^2, basically 15 times the basic x^2 function. So if x=5, then the value becomes 15 * (5)^2 = 15*25 = 375.

    SkyEye on
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  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    In what context?

    "Find the numerical coefficients in the below problems"

    Rhino on
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  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    SkyEye wrote: »
    Basically, you simply take the coefficient and multiply it by the variable term its in front of. ex. 15x^2, basically 15 times the basic x^2 function. So if x=5, then the value becomes 15 * (5)^2 = 15*25 = 375.

    So in the above, what is the coefficient?

    Rhino on
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  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Rhino wrote: »
    SkyEye wrote: »
    Basically, you simply take the coefficient and multiply it by the variable term its in front of. ex. 15x^2, basically 15 times the basic x^2 function. So if x=5, then the value becomes 15 * (5)^2 = 15*25 = 375.

    So in the above, what is the coefficient?
    It's the number in front of your variable.

    15. 15 is the number in front of the variable. 15 is the coefficient.

    Metalbourne on
  • SavantSavant Simply Barbaric Registered User regular
    edited September 2009
    For basic algebra, a coefficient is the constant multiplier of a collection of variables and powers of variables multiplied together, with one for each separate term. So for the function 5x^2 - 8x + 3, the coefficients are 5, -8, and 3, corresponding to the terms 5x^2, -8x, and 3 respectively. If a question asked what the coefficient of x^2 was in that equation you'd answer 5, and if it asked what the coefficient of x was you'd answer -8.

    Coefficient can mean other things in other contexts, but this is the most basic math meaning of the word.

    Savant on
  • MovitzMovitz Registered User regular
    edited September 2009
    Savant wrote: »
    It's the number in front of your variable.

    Movitz on
  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Movitz wrote: »
    Savant wrote: »
    It's the number in front of your variable.

    What about 8x + 9z?

    The answer in back of book (for pratice set) says that 8 is the numeral coefficient, x is the variable coefficent and has a 'strike' though 9 or z (meaning they aren't coefficients). Why aren't 9 or z a coefficient?

    So coefficient can be defined as "something you multiply against"?

    What about this?

    (A + B) 4

    4 would be the numerial coefficient, right? What type of coefficients are A & B?

    Rhino on
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  • DaenrisDaenris Registered User regular
    edited September 2009
    Rhino wrote: »

    What about 8x + 9z?

    The answer in back of book (for pratice set) says that 8 is the numeral coefficient, x is the variable coefficent and has a 'strike' though 9 or z (meaning they aren't coefficients). Why aren't 9 or z a coefficient?

    So coefficient can be defined as "something you multiply against"?

    What about this?

    (A + B) 4

    4 would be the numerial coefficient, right? What type of coefficients are A & B?

    That doesn't seem to make any sense. Does your book give a definition of the "variable, numerical, true, and real coefficients" that you asked about in the original post?
    In mathematics, a coefficient is a constant multiplicative factor of a specific object. For example, in the expression 9x2, the coefficient of x2 is 9.

    from Wikipedia

    If A and B are variables, then in 4(A+B), 4 is the coefficient. In 8x + 9z, 8 and 9 are the coefficients.

    Daenris on
  • Casually HardcoreCasually Hardcore Once an Asshole. Trying to be better. Registered User regular
    edited September 2009
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.

    Casually Hardcore on
  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Daenris wrote: »
    Rhino wrote: »

    That doesn't seem to make any sense. Does your book give a definition of the "variable, numerical, true, and real coefficients" that you asked about in the original post?

    no, it's a "review" chapater before the real stuff starts. It says we should of already taken and know this stuff.

    Rhino on
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  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.

    Why isn't 9 a coefficient?

    Rhino on
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  • DemerdarDemerdar Registered User regular
    edited September 2009
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.

    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Demerdar on
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  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Demerdar wrote: »
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.

    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Math books are always pulling this kind of shit.

    But yeah, in terms of x, 9z isn't a coefficient.

    Actually, wikipedia spells it out pretty good: a coefficient is a constant multiplicative factor of a specific object.

    Metalbourne on
  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Demerdar wrote: »
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.
    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Math books are always pulling this kind of shit.

    But yeah, in terms of x, 9z isn't a coefficient.

    Actually, wikipedia spells it out pretty good: a coefficient is a constant multiplicative factor of a specific object.

    Thanks guys, I guess I understand.

    In math terminology, what is a "specific object" defined as?

    Rhino on
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  • AwkAwk Registered User regular
    edited September 2009
    what kind of math are they teaching you. jesus.

    Awk on
  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Rhino wrote: »
    Demerdar wrote: »
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.
    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Math books are always pulling this kind of shit.

    But yeah, in terms of x, 9z isn't a coefficient.

    Actually, wikipedia spells it out pretty good: a coefficient is a constant multiplicative factor of a specific object.

    Thanks guys, I guess I understand.

    In math terminology, what is a "specific object" defined as?

    It's not really a math term, it's just anything that the focus is on. Like the focus being on x in your math book, even though it wasn't stated. As in "What is the coefficient of x in the equation 3x + 2y"
    x is the specific object that we're talking about here.

    Metalbourne on
  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Rhino wrote: »
    Demerdar wrote: »
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.
    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Math books are always pulling this kind of shit.

    But yeah, in terms of x, 9z isn't a coefficient.

    Actually, wikipedia spells it out pretty good: a coefficient is a constant multiplicative factor of a specific object.

    Thanks guys, I guess I understand.

    In math terminology, what is a "specific object" defined as?

    It's not really a math term, it's just anything that the focus is on. Like the focus being on x in your math book, even though it wasn't stated. As in "What is the coefficient of x in the equation 3x + 2y"
    x is the specific object that we're talking about here.

    ok.

    So coefficient just means "number" or variable that we're "concerned" with. got it. Thanks.

    Rhino on
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  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    Awk wrote: »
    what kind of math are they teaching you. jesus.

    ?


    It's a refresher course.

    Rhino on
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  • AwkAwk Registered User regular
    edited September 2009
    Fair enough. Don't get discouraged if you're having trouble grasping those terms though.

    Awk on
  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Rhino wrote: »
    Rhino wrote: »
    Demerdar wrote: »
    Rhino wrote: »
    Well hold up, 8x + 9z makes no sense. It's just a bunch of numbers and symbols.

    That is the example from the book.
    But F(x) = 8x + 9z makes sense. 8 would be a coefficient and 9z are constants.
    Why isn't 9 a coefficient?

    Because the variable in question is "x", not z.

    If it were F(z) = 8x + 9z then 9 would be the coefficient.

    Math books are always pulling this kind of shit.

    But yeah, in terms of x, 9z isn't a coefficient.

    Actually, wikipedia spells it out pretty good: a coefficient is a constant multiplicative factor of a specific object.

    Thanks guys, I guess I understand.

    In math terminology, what is a "specific object" defined as?

    It's not really a math term, it's just anything that the focus is on. Like the focus being on x in your math book, even though it wasn't stated. As in "What is the coefficient of x in the equation 3x + 2y"
    x is the specific object that we're talking about here.

    ok.

    So coefficient just means "number" or variable that we're "concerned" with. got it. Thanks.

    This is probably going to confuse you, but no.

    While a coefficient can be any real number, it's not a variable.

    x is a variable. In other words, letters.

    Metalbourne on
  • Inquisitor77Inquisitor77 2 x Penny Arcade Fight Club Champion A fixed point in space and timeRegistered User regular
    edited September 2009
    OK guys, human cognition 101 - people learn concepts through examples. Stop using terminology.

    1) 3x
    2) 7y
    3) 15z + 2n
    4) 6a(2x-9y)
    5) 3 + 48b - v/12 + 6g


    1) The coefficient of x is 3.
    2) The coefficient of y is 7.
    3) The coefficient of z is 15. The coefficient of n is 2.
    4) The coefficient of a is 6. The coefficient of x is 2. The coefficient of y is 9.
    5) The coefficient of b is 48. The coefficient of g is 6. The coefficient of v is 1/12.

    Sensing a pattern here? Later on you can worry about trick questions and specific objects. The basic concept is the same everywhere. These guys are just making you think too hard about something basic.

    Inquisitor77 on
  • SavantSavant Simply Barbaric Registered User regular
    edited September 2009
    OK guys, human cognition 101 - people learn concepts through examples. Stop using terminology.

    1) 3x
    2) 7y
    3) 15z + 2n
    4) 6a(2x-9y)
    5) 3 + 48b - v/12 + 6g


    1) The coefficient of x is 3.
    2) The coefficient of y is 7.
    3) The coefficient of z is 15. The coefficient of n is 2.
    4) The coefficient of a is 6. The coefficient of x is 2. The coefficient of y is 9.
    5) The coefficient of b is 48. The coefficient of g is 6. The coefficient of v is 1/12.

    Sensing a pattern here? Later on you can worry about trick questions and specific objects. The basic concept is the same everywhere. These guys are just making you think too hard about something basic.

    Er, I'm pretty sure that number 4 is a bit off. Maybe you meant something else, because typically you want to expand out terms to get coefficients. So 6a(2x - 9y) = 12a*x - 54a*y, which has the coefficient 12 for a*x and -54 for a*y.

    The question should be specific on what coefficient(s) in particular they are asking for if there is potential for ambiguity.

    Savant on
  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Savant wrote: »
    OK guys, human cognition 101 - people learn concepts through examples. Stop using terminology.

    1) 3x
    2) 7y
    3) 15z + 2n
    4) 6a(2x-9y)
    5) 3 + 48b - v/12 + 6g


    1) The coefficient of x is 3.
    2) The coefficient of y is 7.
    3) The coefficient of z is 15. The coefficient of n is 2.
    4) The coefficient of a is 6. The coefficient of x is 2. The coefficient of y is 9.
    5) The coefficient of b is 48. The coefficient of g is 6. The coefficient of v is 1/12.

    Sensing a pattern here? Later on you can worry about trick questions and specific objects. The basic concept is the same everywhere. These guys are just making you think too hard about something basic.

    Er, I'm pretty sure that number 4 is a bit off. Maybe you meant something else, because typically you want to expand out terms to get coefficients. So 6a(2x - 9y) = 12a*x - 54a*y, which has the coefficient 12 for a*x and -54 for a*y.

    The question should be specific on what coefficient(s) in particular they are asking for if there is potential for ambiguity.

    Technically you're right. (which is the best kind of right)

    Metalbourne on
  • RhinoRhino TheRhinLOL Registered User regular
    edited September 2009
    ok, thanks for the examples.

    Rhino on
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  • Al_watAl_wat Registered User regular
    edited September 2009
    Savant wrote: »
    OK guys, human cognition 101 - people learn concepts through examples. Stop using terminology.

    1) 3x
    2) 7y
    3) 15z + 2n
    4) 6a(2x-9y)
    5) 3 + 48b - v/12 + 6g


    1) The coefficient of x is 3.
    2) The coefficient of y is 7.
    3) The coefficient of z is 15. The coefficient of n is 2.
    4) The coefficient of a is 6. The coefficient of x is 2. The coefficient of y is 9.
    5) The coefficient of b is 48. The coefficient of g is 6. The coefficient of v is 1/12.

    Sensing a pattern here? Later on you can worry about trick questions and specific objects. The basic concept is the same everywhere. These guys are just making you think too hard about something basic.

    Er, I'm pretty sure that number 4 is a bit off. Maybe you meant something else, because typically you want to expand out terms to get coefficients. So 6a(2x - 9y) = 12a*x - 54a*y, which has the coefficient 12 for a*x and -54 for a*y.

    The question should be specific on what coefficient(s) in particular they are asking for if there is potential for ambiguity.

    I might be wrong and this is kind of nitpicky, but couldn't you say that for: 6a(2x-9y), 6 is the coefficient of a(2x-9y) (ie: treating a(2x-9y) as one term affected by 6).

    ...like i said kinda really nitpicky....

    Al_wat on
  • Casually HardcoreCasually Hardcore Once an Asshole. Trying to be better. Registered User regular
    edited September 2009
    6a(2x-9y), 6 is the coefficient of a(2x-9y) (ie: treating a(2x-9y) as one term affected by 6)

    No, a(2x-9y) is two terms; 2xa - 2ya.

    Casually Hardcore on
  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    6a(2x-9y), 6 is the coefficient of a(2x-9y) (ie: treating a(2x-9y) as one term affected by 6)

    No, a(2x-9y) is two terms; 2xa - 2ya.

    I'm sure he meant factor in that.

    Metalbourne on
  • DemerdarDemerdar Registered User regular
    edited September 2009
    I cant imagine why they would be teaching you this for more than 5 minutes.

    It's almost trivial.

    Demerdar on
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  • MetalbourneMetalbourne Inside a cluster b personalityRegistered User regular
    edited September 2009
    Demerdar wrote: »
    I cant imagine why they would be teaching you this for more than 5 minutes.

    It's almost trivial.

    It seems like it is, but learning the vocabulary of math is pretty important.

    Metalbourne on
  • DemerdarDemerdar Registered User regular
    edited September 2009
    Demerdar wrote: »
    I cant imagine why they would be teaching you this for more than 5 minutes.

    It's almost trivial.

    It seems like it is, but learning the vocabulary of math is pretty important.

    You learn by actually doing math, not nitpicking about the definition of a coefficient.

    Demerdar on
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  • Casually HardcoreCasually Hardcore Once an Asshole. Trying to be better. Registered User regular
    edited September 2009
    Demerdar wrote: »
    Demerdar wrote: »
    I cant imagine why they would be teaching you this for more than 5 minutes.

    It's almost trivial.

    It seems like it is, but learning the vocabulary of math is pretty important.

    You learn by actually doing math, not nitpicking about the definition of a coefficient.

    No. There's a huge difference between (4x+9)dx and 4x+9dx. Getting your math definitions and nomenclature correct now will help you immensely when you continue your math education.

    Casually Hardcore on
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