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Algebraically retarded
Deebaseron my way to work in a suit and a tieAhhhh...come on fucking guyRegistered Userregular
I have these values that have been discounted 35% of x and I need to find x. I haven't had my coffee yet and just thought of this approach in the shower. It's a good approach, but every way I look at the actual math in the fog of morning, I just can't crack it.
The way I'm reading it is that you've got some value (let's say 65) that's been discounted 35% and you want to know the original value (basically a problem like "You go to the store and see a lol on sale for $65, it's been marked down 35% of the original price, what was the original price?")
Maybe? If that's the case you're going to take your discounted value (which is actually equal to 65% of the original price, since it's discounted by 35%) and divide it by that percentage, so 65/.65 says that original cost (x) is $100.
This would look like values=.65x, where your values are already discounted by 35%.
Not sure if that's what you were looking for, hopefully it helped some.
Edited for bad grammar. It's a math thread, but that's no excuse
Yep. One simple way to think of it is that to apply a 35% discount you multiply the original cost x by (100% - 35%), so to undo that you reverse the operation.
x * (1 - .35) = <your value>
x = <your value> / (1 - .35)
FunkyWaltDogg on
0
Deebaseron my way to work in a suit and a tieAhhhh...come on fucking guyRegistered Userregular
edited March 2010
That is exactly it, Funky!
Thank you very much everyone. I should probably be ashamed of myself.
Posts
see below.
Maybe? If that's the case you're going to take your discounted value (which is actually equal to 65% of the original price, since it's discounted by 35%) and divide it by that percentage, so 65/.65 says that original cost (x) is $100.
This would look like values=.65x, where your values are already discounted by 35%.
Not sure if that's what you were looking for, hopefully it helped some.
Edited for bad grammar. It's a math thread, but that's no excuse
x * (1 - .35) = <your value>
x = <your value> / (1 - .35)
Thank you very much everyone. I should probably be ashamed of myself.
Please lock.