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Simple physics problem

dexterdexter Registered User regular
edited May 2010 in Help / Advice Forum
I'm trying to solve a problem for one of my mates who has to take a basic physics unit for his degree, but I can't sort out how to solve it. I feel completely lost without vectors or anything like that to work with.

It's actually a little bit embarrassing.. how would you go about solving this? x has a speed of 8km/s and y has a speed of 4.5km/s. x hits the finish line 78 seconds before y does. what's the distance from start to finish?

so all i could do was find that y is 351km behind when x hits the end. from there i over thought it and did some obscure things like dividing 351 by 0.56 and getting a distance of 626.78km. The way I solved this is hardly built off anything solid, so I doubt it's correct.

I know this is tragic, I have no idea why I can't do this. I could never be a teacher!

Thanks in advance, guys.

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dexter on

Posts

  • Fuzzy Cumulonimbus CloudFuzzy Cumulonimbus Cloud Registered User regular
    edited May 2010
    Okay so Distance = Rate*Time
    x (rate) = 8 km/s
    y (rate) = 4.5 km/s
    y (time) = x + 78
    x (time) = y - 78
    go from there

    Fuzzy Cumulonimbus Cloud on
  • dexterdexter Registered User regular
    edited May 2010
    okay so I set up a simultaneous equation, and end up with 931.25km. how does this look? I'm terrible at these sorts of problems.

    8(y-78)=4.5(x+78) etc.

    dexter on
    3694663-1.png
  • VirumVirum Registered User regular
    edited May 2010
    Not quite. You have multiple unknowns and you have the difference in time twice as large as it should be.

    You should have one variable for time, t.

    x's time is just t,
    y's time is t + 78

    Note, both objects have to traverse the same amount of distance, just one takes longer. So we can say that:

    d = 8t
    d = 4.5(t+78)

    If two things are equal to the same variable, they are equal to each other.

    4.5(t+78) = 8t

    Solve for t, and substitute into one of the equations to find distance.

    Virum on
  • dexterdexter Registered User regular
    edited April 2014
    Thanks a lot you two!

    dexter on
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