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[Solved] Imaginary numbers math problem
Crimsonmonkey
Registered User regular
Registered User regular
I am having some trouble working out a problem solving for x and y involving imaginary numbers. Each time it seems I end up in a loop where the definition of x involves y and vice versa, so substitution back into the answer doesn't work. I suspect it is just me forgetting some basic principal since it has been a long time since I have done any math, but hopefully someone can show me where I am going wrong.
The problem:
(2x+3y) + (5x-2y)i = 13 + 4i
Solve for x & y
Attempt:
X:
2x + 3y = 13
2x = 13-3y
x = 13/2 -3/2y
Y:
5xi-2yi = 4i
5x-2y = 4
-2y=4-5x
y=-2+5/2x
From here it all breaks down into a loop if I substitute X or Y back into the original equation, so I figure I have made a mistake at this point.
The problem:
(2x+3y) + (5x-2y)i = 13 + 4i
Solve for x & y
Attempt:
X:
2x + 3y = 13
2x = 13-3y
x = 13/2 -3/2y
Y:
5xi-2yi = 4i
5x-2y = 4
-2y=4-5x
y=-2+5/2x
From here it all breaks down into a loop if I substitute X or Y back into the original equation, so I figure I have made a mistake at this point.
Crimsonmonkey on
0
Posts
2x + 3y = 13
5x - 2y = 4
Two equations, two unknowns, solve them.
Thanks for the help.