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b0bd0d
Registered User regular

okay, what am I doing wrong?

0

## Posts

You know all the angles. You want to relate the hypotenuse to either x or y. Since sin and cos both relate to the hypotenuse (sin@ = opposite/hyptenuse and cos@ = adjacent/hypotenuse) you can use either of them.

So, sin45degrees = (root2) / x and sin45degrees = (root2)/y

You can see this from the graph, correct?

Just solve for the unknown variable. You know how to do that?

Al_watonb0bd0donso:

1^2 + 1^2 = ?

1 + 1 = 2

take square root of answer to find hypotenuse:

sqrt(2)

It's right.

Virumonx^2 + y^2 = h^2

1 + 1 = h^2

2 = h^2

h = sqrt(2)

Edit: beaten

Bob Sapponwait, what's the sqr of 2?

b0bd0donSmug DucklingonAnd you should never use the law of sines and cosines to find measurements for a right triangle.

mrcheesypantsonb0bd0donMy advice is to just memorize those 3 configurations, you'll find them often enough.

Also, if you don't know the unit circle, just keep working this way. Better to learn one way 100% than 2 ways 1/2.

Iceman.USAFon"The sqr of 2 is 4. The sqrt of 2 is an irrational number, so you can't write it, but it is approximately 1.41."

Yeah, but that triangle says it's 1...doesn't it?

b0bd0donAl_waton