The new forums will be named Coin Return (based on the most recent vote)! You can check on the status and timeline of the transition to the new forums here.
The Guiding Principles and New Rules document is now in effect.

General Math Question (Solved)

Spectral SwallowSpectral Swallow Registered User regular
edited November 2008 in Help / Advice Forum
Maybe I'm just glitching or something but for some reason I can't get the division to work for me here.

Okay, so take for example you wanted to know what 6 X 10 is. Instead of just saying '60' you could go:

4 X 10 = 40
2 X 10 = 20

And then add up the answers. Basically breaking it down into a simpler problem. But when you try to do something similar in division:

60 ÷ 10 = 6

You can't just go:

60 ÷ 5 = 12
60 ÷ 5 = 12

And then add them. So what exactly am I missing here?

Spectral Swallow on

Posts

  • xraydogxraydog Registered User regular
    edited November 2008
    It works if you break down the dividends instead of the divisors:

    60 / 10 = 6

    40 / 10 = 4

    20 / 10 = 2

    xraydog on
  • edited November 2008
    This content has been removed.

  • Spectral SwallowSpectral Swallow Registered User regular
    edited November 2008
    Yeah but that's doesn't really help where I'm going with it though. An example of what I'd be kinda trying to get to would be:

    3x+2y+5
    3z+14


    And then just doing:

    3x+2y+5 / 3z
    and
    3x+2y+5 / 14

    You see? What I'm trying to do isn't in the book or anything, I was just curious why it wouldn't work.

    Spectral Swallow on
  • oldsakoldsak Registered User regular
    edited November 2008
    Remember dividing a number by a number is like multiplying it by 1/(that number).

    so for your example the appropriate thing to do would be
    60 * 1/20

    When you do 60 ÷ 5 you're multiplying the divisor (10 or 1/10) by 2 instead of dividing it by 2.

    oldsak on
  • edited November 2008
    This content has been removed.

  • Peter EbelPeter Ebel CopenhagenRegistered User regular
    edited November 2008
    Because division takes priority over addition. What you'd end up with there is:

    (3x/3z+14)+(2y/3z+14)+(5/3z+14)

    Peter Ebel on
    Fuck off and die.
  • edited November 2008
    This content has been removed.

  • GdiguyGdiguy San Diego, CARegistered User regular
    edited November 2008
    mcdermott wrote: »
    Yeah but that's doesn't really help where I'm going with it though. An example of what I'd be kinda trying to get to would be:

    3x+2y+5
    3z+14


    And then just doing:

    3x+2y+5 / 3z
    and
    3x+2y+5 / 14

    You see? What I'm trying to do isn't in the book or anything, I was just curious why it wouldn't work.

    It doesn't work because that's not how division works. I'm not sure of the best way to explain it, but basically the easiest way to understand why this won't work is to ignore the idea of "division," and instead thinking of division as multiplication by the inverse (which it is). So instead of dividing by 6, you multiply by 1/6.

    Then just realize that 1/(x+y) does not equal 1/x + 1/y...it equals A/x + B/y, where A and B are values to be determined though a fun process known as partial fraction decomposition.

    If you're in need of proof that 1/(x+y) != (1/x)+(1/y), then just substitute constants in for x and y to prove it to yourself.


    To be more specific, multiplication has the distributive property, which basically states that a * (b + c) = a * b + a * c. So, as above, 10 * (4 + 2) = 10 * 4 + 10 * 2.

    Division doesn't have that property, as stated well in the post above

    Gdiguy on
  • Peter EbelPeter Ebel CopenhagenRegistered User regular
    edited November 2008
    Gdiguy wrote: »
    mcdermott wrote: »
    Yeah but that's doesn't really help where I'm going with it though. An example of what I'd be kinda trying to get to would be:

    3x+2y+5
    3z+14


    And then just doing:

    3x+2y+5 / 3z
    and
    3x+2y+5 / 14

    You see? What I'm trying to do isn't in the book or anything, I was just curious why it wouldn't work.

    It doesn't work because that's not how division works. I'm not sure of the best way to explain it, but basically the easiest way to understand why this won't work is to ignore the idea of "division," and instead thinking of division as multiplication by the inverse (which it is). So instead of dividing by 6, you multiply by 1/6.

    Then just realize that 1/(x+y) does not equal 1/x + 1/y...it equals A/x + B/y, where A and B are values to be determined though a fun process known as partial fraction decomposition.

    If you're in need of proof that 1/(x+y) != (1/x)+(1/y), then just substitute constants in for x and y to prove it to yourself.


    To be more specific, multiplication has the distributive property, which basically states that a * (b + c) = a * b + a * c. So, as above, 10 * (4 + 2) = 10 * 4 + 10 * 2.

    Division doesn't have that property, as stated well in the post above

    Division has distributive property. Example: (4+2)/2 = (4/2)+(2/2) = 2+1 = 3

    Peter Ebel on
    Fuck off and die.
  • edited November 2008
    This content has been removed.

  • musanmanmusanman Registered User regular
    edited November 2008
    Division distributes just fine, that's not the issue.

    If you have

    3x+2y+5
    3z+14

    you can break it down, but it's 3x / (3z+14) + 2y / (3z+14) + 5 / (3z+14)

    what you need to realize is you're dividing by a quantity 3z+14...and based on the order of ops the parenthesis come before the division

    musanman on
    sic2sig.jpg
  • Spectral SwallowSpectral Swallow Registered User regular
    edited November 2008
    Thanks guys, I understand it a lot better now, it was just one of those things like, 'hmm, it SHOULD work, since it works with multiplication, and division is just multiplying by the recip' but for some reason my mind just wasn't working.

    Thanks for the help.

    Spectral Swallow on
Sign In or Register to comment.