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Physics problem, might just be a calculator problem?

Chop LogicChop Logic Registered User regular
edited February 2009 in Help / Advice Forum
So the question is:

Calculate the energy of the transitions from the n = 4,5,6 energy levels to the n = 3 level for the hydrogen atom using the Bohr formula.

I'm assuming he means this equation (sorry, I'll just write this phonetically because I don't have any idea how to write the symbols):

Delta E = ((e^2)(m sub e) / 8 Epsilon^2 h^2))((1/n sub f ^2) - (1/n sub i^2))

The problem is, the numerator of the first part of the equation, e^2(m sub e) , is so small that on the three calculators I've tried, it just works out to zero, and the whole equation becomes zero.

Am I doing this right? It's pretty frustrating because this is the first problem in a long list of problems and if I can't get this answer I can't do the rest of the problems, but I can't figure out what I should be doing.

Thanks a lot.

Chop Logic on

Posts

  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    dude, just so you know, this is really more chemistry than physics.

    Dunadan019 on
  • TerrendosTerrendos Decorative Monocle Registered User regular
    edited February 2009
    Can you switch it into Scientific Notation? The small number, I mean.

    Terrendos on
  • Chop LogicChop Logic Registered User regular
    edited February 2009
    I'm not sure what you mean. I mean, I know what scientific notation is, I just don't know what you're asking. What I'm saying is that when I put in that equation of numbers, I get a zero. When I put it in in pieces, the numerator is coming out to be zero when I know that it isn't. I think the number is just so small that the calculator is rounding.


    Do I just need to buy one of those expensive TI calculators? I am using a scientific calculator I borrowed from my roommate and even that is giving me zeros.

    Chop Logic on
  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    Chop Logic wrote: »
    Okay, thanks.

    I am also having the same problem for this question now. I am trying to find the uncertainty of momentum for something using this equation:

    (Delta x)(Delta p) = h/2

    Except that when I put h/2 into either of the three calculators I'm using:

    (6.63 x 10^-34)/2

    I get zero.

    What the fuck.

    Do I just need to buy one of those expensive TI calculators? I am using a scientific calculator I borrowed from my roommate and even that is giving me zeros.

    take that 10^-34 and multiply it in at the end.

    Dunadan019 on
  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    Chop Logic wrote: »
    I'm not sure what you mean. I mean, I know what scientific notation is, I just don't know what you're asking. What I'm saying is that when I put in that equation of numbers, I get a zero. When I put it in in pieces, the numerator is coming out to be zero when I know that it isn't. I think the number is just so small that the calculator is rounding.


    Do I just need to buy one of those expensive TI calculators? I am using a scientific calculator I borrowed from my roommate and even that is giving me zeros.

    whats the actual value of the very small number?

    also, what is the value of the other part as well.

    Dunadan019 on
  • Chop LogicChop Logic Registered User regular
    edited February 2009
    ^That equation worked when I put it into a different calculator, but I still can't get the first one.

    Edit: One second, I will write out a more accurate description of what is happening.

    Chop Logic on
  • Chop LogicChop Logic Registered User regular
    edited February 2009
    In doing the first question I explained above, if I put it in all together, I get zero.

    So I'm putting it in in pieces.

    The first part, (e^4)(m sub e) , is:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)

    When I put it into the calculator, I keep getting zero as an answer. I think it's because the number is so small that the calculator is rounding it down to zero, but even the scientific calculator is doing that. What should I do?

    Edit: I changed the mode on the scientific calculator, and now it's giving me 0 x 10^00 . Awesome.

    Chop Logic on
  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    for example, if your equation is x=y*z

    and you want to find x. y = 5 and z = 1x10^-100. when you put this into a calculator it will give you a zero. the most accurate answer though is (5x1)x10^-100 or 5x10^-100.

    if y = 5x10^50, then it would be (5x1)x10^(50-100) or 5x10^-50

    Dunadan019 on
  • physi_marcphysi_marc Positron Tracker In a nutshellRegistered User regular
    edited February 2009
    I think you just need to figure out a way for your calculator to display scientific notation. No, you don't need to buy an expensive TI one. All cheap scientific calculator should have an option to display the answers in scientific notation (e.g. 6.63E-34).

    Also, yes, the answer will be quite small indeed. I think your formula gives you someting in Joules. In this case, it would probably be better to convert it so you get the answer in eV. But if I just lost you, don't worry about it.

    physi_marc on
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  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    Chop Logic wrote: »
    In doing the first question I explained above, if I put it in all together, I get zero.

    So I'm putting it in in pieces.

    The first part, (e^4)(m sub e) , is:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)

    When I put it into the calculator, I keep getting zero as an answer. I think it's because the number is so small that the calculator is rounding it down to zero, but even the scientific calculator is doing that. What should I do?

    the answer is (1.6x9.11)x10^(-31-19) or 14.576x10^-50

    Dunadan019 on
  • CycloneRangerCycloneRanger Registered User regular
    edited February 2009
    Google Calculator can handle numbers up to at least 1.0E300, and it can parse scientific notation as well. Just type your equation (with constants inserted) into Google.

    CycloneRanger on
  • Chop LogicChop Logic Registered User regular
    edited February 2009
    I just found one of the nicer scientific notation calculators, and it keeps rounding it down also.

    I also found a setting to change all answers into scientific notation, and now it's giving me 0 ^ 0.

    Chop Logic on
  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    whats this part? 8 Epsilon^2 h^2))((1/n sub f ^2) - (1/n sub i^2))

    give the numbers.

    Dunadan019 on
  • Chop LogicChop Logic Registered User regular
    edited February 2009
    Google Calculator can handle numbers up to at least 1.0E300, and it can parse scientific notation as well. Just type your equation (with constants inserted) into Google.

    YES. This worked.

    Thanks a lot everyone for helping me out.

    Chop Logic on
  • Marty81Marty81 Registered User regular
    edited February 2009
    Chop Logic wrote: »
    In doing the first question I explained above, if I put it in all together, I get zero.

    So I'm putting it in in pieces.

    The first part, (e^4)(m sub e) , is:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)

    When I put it into the calculator, I keep getting zero as an answer. I think it's because the number is so small that the calculator is rounding it down to zero, but even the scientific calculator is doing that. What should I do?

    Edit: I changed the mode on the scientific calculator, and now it's giving me 0 x 10^00 . Awesome.

    You can also do some algebra:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)
    =
    (1.6^4) x (10^-19)^4 x (9.11 x 10^-31)
    =
    (1.6^4x9.11) x (10^-19)^4 x (10^-31)

    and go from there. The problem you were having with your scientific calculator is clear - once you multiply that out, your exponent on the 10 is less than -100. Most calculators can only handle exponents on the 10 in scientific notation between -100 and 100.

    Marty81 on
  • Dunadan019Dunadan019 Registered User regular
    edited February 2009
    Marty81 wrote: »
    Chop Logic wrote: »
    In doing the first question I explained above, if I put it in all together, I get zero.

    So I'm putting it in in pieces.

    The first part, (e^4)(m sub e) , is:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)

    When I put it into the calculator, I keep getting zero as an answer. I think it's because the number is so small that the calculator is rounding it down to zero, but even the scientific calculator is doing that. What should I do?

    Edit: I changed the mode on the scientific calculator, and now it's giving me 0 x 10^00 . Awesome.

    You can also do some algebra:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)
    =
    (1.6^4) x (10^-19)^4 x (9.11 x 10^-31)
    =
    (1.6^4x9.11) x (10^-19)^4 x (10^-31)

    and go from there. The problem you were having with your scientific calculator is clear - once you multiply that out, your exponent on the 10 is less than -100. Most calculators can only handle exponents on the 10 in scientific notation between -100 and 100.

    just so you know, when you multiply numbers with exponents that have the same base, you add the exponents and keep the base

    10^3 x 10^3 (which is 1000x1000) does not equal 10^9 (1,000,000,000) but 10^6 (1,000,000)

    Dunadan019 on
  • Marty81Marty81 Registered User regular
    edited February 2009
    Dunadan019 wrote: »
    Marty81 wrote: »
    Chop Logic wrote: »
    In doing the first question I explained above, if I put it in all together, I get zero.

    So I'm putting it in in pieces.

    The first part, (e^4)(m sub e) , is:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)

    When I put it into the calculator, I keep getting zero as an answer. I think it's because the number is so small that the calculator is rounding it down to zero, but even the scientific calculator is doing that. What should I do?

    Edit: I changed the mode on the scientific calculator, and now it's giving me 0 x 10^00 . Awesome.

    You can also do some algebra:

    (1.6 x 10^-19)^4 (9.11 x 10^-31)
    =
    (1.6^4) x (10^-19)^4 x (9.11 x 10^-31)
    =
    (1.6^4x9.11) x (10^-19)^4 x (10^-31)

    and go from there. The problem you were having with your scientific calculator is clear - once you multiply that out, your exponent on the 10 is less than -100. Most calculators can only handle exponents on the 10 in scientific notation between -100 and 100.

    just so you know, when you multiply numbers with exponents that have the same base, you add the exponents and keep the base

    10^3 x 10^3 (which is 1000x1000) does not equal 10^9 (1,000,000,000) but 10^6 (1,000,000)

    Right, so the result would be
    59.703296x10^-107
    =
    5.9703296x10^-106

    Marty81 on
  • Joe ChemoJoe Chemo Registered User regular
    edited February 2009
    I ran into this problem in p-chem all the time.

    The trick is to break it down into parts, and alternate entering a part from the numerator and from the denominator. Breaking it into parts doesn't work if you enter all of the denominator parts consecutively.

    Joe Chemo on
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