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Acid-Base neutralization+ Molecular Weight
vash11
Registered User regular
Registered User regular
This is a problem that i know will be on my Acid Base Equilibrium test tomorrow in College Now Chemistry.
" X ml of (insert random base, NaOH i think?) with a 1.0084 molarity is used to neutralize 5 grams of a Weak Acid in Y ml of solution. What is the molecular weight of the Weak Acid."
NOTE: On the test we are given the ml of each solution; but, they were large numbers with many significant figures so i can't remember them.
I think i know how to solve this problem, but i want to double check and my textbook doesn't have an example of a problem that is set up in this exact way.
The way i would go about solving this problem is by first figuring out the total amount of NaOH present in millimols. Since they neutralize they must be present in equal amounts(Stoichiometrically, that is), and by knowing the amount of millimols and how much they weigh(5g), i can find the molecular weight by simple multiplication.
Like i said, I'm fairly sure i know this. But almost every other question on this test is extremely difficult, so I'm kind of suspicious.
If any chemists/science types present could just quickly make sure I'm doing this right, it would be much appreciated.
" X ml of (insert random base, NaOH i think?) with a 1.0084 molarity is used to neutralize 5 grams of a Weak Acid in Y ml of solution. What is the molecular weight of the Weak Acid."
NOTE: On the test we are given the ml of each solution; but, they were large numbers with many significant figures so i can't remember them.
I think i know how to solve this problem, but i want to double check and my textbook doesn't have an example of a problem that is set up in this exact way.
The way i would go about solving this problem is by first figuring out the total amount of NaOH present in millimols. Since they neutralize they must be present in equal amounts(Stoichiometrically, that is), and by knowing the amount of millimols and how much they weigh(5g), i can find the molecular weight by simple multiplication.
Like i said, I'm fairly sure i know this. But almost every other question on this test is extremely difficult, so I'm kind of suspicious.
If any chemists/science types present could just quickly make sure I'm doing this right, it would be much appreciated.
vash11 on
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The only thing I would say is, because molecular weight is a grams per mole ratio, what you'd want to do is divide the weight of the acid by the number of moles, rather than multiply (unless you just meant to multiply by the inverse). Also, be sure your units jive with eachother. Be sure to use grams per mole, or milligrams per millimole, or else you'll be off by a few orders of magnitude.