Hi
This is not homework - it's just maths for a hobbygame I'm thinking about.
I have 3 groups of 5 elements - let's call them A B C D E, M N O P Q, and V W X Y Z.
If a given entity is assigned one from each group, e.g. AMV or ANW, or even CYV - how many possible entities are there?
This is assuming, by the way, that AMV and VMA are distinct from each other. Order matters.
I think it's a huge amount - 625 maybe? But I'm not sure.
Can someone help me out please? Thanks.
I figure I could take a bear.
Posts
Y and V are in the same group. Is this a typo or do you allow multiple elements from the same group?
order does matter adds a *3! AKA 6
so 5*5*5*6 is 750?
its been awhile since i've done prob, but that makes my sanity check.
You have five elements in each group, so the number of possible combinations is 5*5*5. Then each combination can be written in 6 different ways by changing the order. So the total is 5*5*5*6 = 750.
15*14*13 = 2730 combinations ?
I have terrible math when it comes to non-algebra stuff though.
Also, CYV doesn't come from each group.
1)Can you pick more than an element in each group ?
2)If yes, can the same element be picked more than once ?
Thanks! That makes complete sense. I knew it was about 5 cubed, and I knew it was about 3!, but I couldn't remember what to do with them.