alright, school asignment so not using real numbers, just need some pointers in the right direction
i have a function
f(x) = (x^3/600) + 60x + 500
and need to get the derivative of this, only problem is, i have no idea how to go about the first part, (x^3/600).
Since there is no x under the fraction, i will get 0 there (or will it disapear leaving me with 3x^2?), so i need to some how get rid of the 600 before i can do anything else.
would this be possible?
(x^3/600) + 60x + 500 = 0
(x^3/600) + 60x = -500 | * 600
x^3 + 3600x = -300000
ninja edit: forgot to mention,
i tried moving the 600 above the fraction sign giving me 3.456789e^-4 * x^3, it gives the correct answer with test numbers but looks ugly as sin
or is there some magic/better way of going about this?
Posts
(x^3)/600
ok
so remember the derivative of x^3 is 3x^2
(1/600)*(3x^2) = (1/200)(x^2) = (x^2)/200 or what Nixon said above
you were massively overthinking this - just remember that constants are always factored out
thanks a lot!
back in the day when I did a lot of calculus, I found it helpful sometimes to think of the equations in terms of Constants x Variables because it made things so much easier to keep separate
for example, your function f(x) above I would rewrite as C1*x^3 + C2*x + C3, then go through the derivation, and then put the constants back in and evaluate
eventually I could see the separation in my head and that actually helped tremendously when we moved on to integration
It makes things a lot easier to see.