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To start, I'm not looking for answers. I just want to know if I'm on the right track. I'm helping my wife with her homework, and the powerpoint notes aren't great, so here we go.
The scenario is a 150lb subject walking up 4m worth of stairs in 12 seconds. First, we are supposed to convert the subject's weight into Newtons, which gives us 675 (Actually, I'm not so sure about this. Now I'm getting 667?). Then, the work in Joules. Work=forcexdistance, so W=675x4m, which would be W=2700? Then, we are supposed to convert it into Power. Power=Work/time, so P=675/12s?
Basically, are we on the right track? Thanks for any help.
Ok, double checked the Newtons. I did the formula, and checked with google conversions, and it should be 667. Thanks for all the help so far, I thought we were on the right track, but I needed some confirmation. One more question. The problem also gives the time the subject walked up the stairs (12 seconds), and the time it took to run up the stairs (4). Now, using the formulas, the Work should be the same for both times, but the Power would be different? So, the subject did the same amount of work (covered the same distance) regardless of speed, but generated more Power the second time because of increased speed?
Everything else looks right, so long as that 4 meters is vertical displacement. The distance has to be in the same direction as the force (which is up--opposite gravity).
EDIT: Metalbourne caught your numeric error and you're correct, the work is the same but it takes more power to do it more quickly.
Everything else looks right, so long as that 4 meters is vertical displacement. The distance has to be in the same direction as the force (which is up--opposite gravity).
I didn't even think of that, but yes, its vertical
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A simpler way to conceptualize this is to calculate the potential energy change, though.
He wrote work/time, but reused the weight. It needs to be 2700N*M/12s
Everything else looks right, so long as that 4 meters is vertical displacement. The distance has to be in the same direction as the force (which is up--opposite gravity).
EDIT: Metalbourne caught your numeric error and you're correct, the work is the same but it takes more power to do it more quickly.
Yeah, my bad. In my mind I had already converted to Newtons, but failed to do so on paper. Thanks for catching it.
I didn't even think of that, but yes, its vertical