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Napalm Donkey
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If you want, you can solve for either R as a function of phi, or phi as a function of r, but seeing how your initial equation wasn't solved for either X or Y, i don't think you need to.
GT: Tanky the Tank
Black: 1377 6749 7425
ax^2 + bx + c = 0.
You know how to solve those, right?
Get this equation to look like one in quadratic form:
R^2 + 6Rcos(phi)-2Rsin(phi) - 6 = 0
Remember the quadratic form: ax^2 +bx + c (1)
Think of R as 'x' , so lets just replace R as x:
x^2 + 6xcos(phi) - 2xsin(phi) - 6 = 0
So lets get this ^ to look like (1)
x^2 + x(6cos(phi) - 2sin(phi)) - 6 = 0
therefore your coefficients in (1) are:
a=1
b=6cos(phi) - 2sin(phi)
c = -6
And there you go, solve the quadratic equation and you will have TWO equations that describe r as a function of phi.
Change phi as you like and plot R accordingly.
GT: Tanky the Tank
Black: 1377 6749 7425