C++ help

curby

I'm trying to make a global pointer variable of type node in C++ in managed mode. I get this error:

Error 1 error C3145: 'start' : global or static variable may not have managed type 'node ^'

ref struct node{
	int data;
	node ^ prev;
	node ^ next;
	};

node ^ start;

int main(...

So how can I make a global variable node?

Sevorak

I don't think you can have a managed handle in global space, at least not without some effort and utility classes. Why do you need it to be global?

curby

I'm making a linked list in managed mode, and I'm trying to use functions. I'm not sure how to pass "node ^ start" to "void addFront()"...

That would be good advice as well.

curby

node addFront(node);

main(...){
if (choice == 1){addFront(start);}
}

node addFront(node^start){}

Error 1 error C2664: 'addFront' : cannot convert parameter 1 from 'node ^' to 'node'

Variations of start in main yield similar results.

Sevorak

Well, first of all I would recommend making a full blown LinkedList class instead of doing it c style with pointers, because managed c++ was made to be more object oriented than c++.

That said, your addFront function's signature should look something like

node ^addFront(node ^list, int data)

Sevorak

curby wrote:

node addFront(node);

main(...){
if (choice == 1){addFront(start);}
}

node addFront(node^start){}

Error 1 error C2664: 'addFront' : cannot convert parameter 1 from 'node ^' to 'node'

Variations of start in main yield similar results.

You're getting that error because you're declaring that addFront takes a 'node' not a 'node ^'. A 'node' and 'node ^' are different types, just like 'int' and 'int *' are different types.

Edit: So you're second definition of addFront is an overload, not the definition of the one you declared above main, because the parameter types differ.